jurassic park by 2026

import re
def count_chars_markdown(text):
# Remove markdown syntax but keep actual readable content
# Strip code blocks, headers, links alt texts etc.
# Very approximate
clean = re.sub(r'[^]`', '', text) # inline code
clean = re.sub(r'^\s#+\s', '', clean, flags=re.MULTILINE) # headers
clean = re.sub(r'[([^]]+)]([^)]+)', r'\1', clean) # links
clean = re.sub(r'![[^]]]([^)]+)', '', clean) # images
clean = re.sub(r'>\s', '', clean) # blockquotes
clean = re.sub(r'[-+]\s+', '', clean) # unordered list markers
clean = re.sub(r'\d+.\s+', '', clean) # ordered list markers
clean = re.sub(r'__|**|_|*', '', clean) # emphasis
clean = re.sub(r'---+', '', clean) # horizontal rules
clean = re.sub(r'\s+', ' ', clean).strip()
return len(clean)

Generate placeholder to check length later
placeholder = "jurassic park by " * 625 # approx 10k chars
count_chars_markdown(placeholder)

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